2x^2-20x-9750=0

Solution for 2x^2-20x-9750=0 equation:

2x^2-20x-9750=0

a = 2; b = -20; c = -9750;
Δ = b2-4ac
Δ = -202-4·2·(-9750)
Δ = 78400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{78400}=280$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-280}{2*2}=\frac{-260}{4}
=-65
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+280}{2*2}=\frac{300}{4}
=75
$